Physics - W.E.P. Question with Solution | TestHub

A simple pendulum has a length of $2\mathrm{m}$ and a bob of mass of $100\mathrm{grams}$. It is whirled in a horizontal plane. If the string breaks under a tension of $10\mathrm{N}$, the angle made by the string with vertical is ${\cos }^{-1}(0.1)$. $\left(g=10\mathrm{m}/{\mathrm{s}}^2\right)$
$\mathrm{L}=2\mathrm{m}$ $\mathrm{m}=\frac{100}{1000}=0.1\mathrm{kg}$ $\mathrm{Tcos}\Phi =mg$ $\mathrm{Tsin}\Phi =\frac{m{v}^2}{R}$ $\cos \Phi =\frac{mg}{T}=\frac{0.1\times 10}{10}=0.1$ $\therefore \Phi ={\cos }^{-1}(0.1)$