During displacement of a body two forces are acting on it simultaneously. Forces are F 1 = 2 i ^ − 2 j ^ and F 2 = i ^ + 5 j ^ . Work done by individual forces on body are ( -8 joule) and ( 2 joule) respectively then displacement of body will be :-

Lets say displacement is a i ^ + b j ^ = d so ⇒ ω 1 = F 1 ⋅ d = 2 a − 2 b = − 8 ⇒ ω 2 = F 2 ⋅ d = a + 5 b = 2 …… ⇒ a = − 3 , b = 1

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PhysicsW.E.P.Calculation of workMedium2 minQB

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During displacement of a body two forces are acting on it simultaneously. Forces are $F_{1} = 2 \hat{i} - 2 \hat{j}$ and $F_{2} = \hat{i} + 5 \hat{j}$ . Work done by individual forces on body are ( -8 joule) and ( 2 joule) respectively then displacement of body will be :-

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Solution:

Lets say displacement is $a \hat{i} + b \hat{j} = d$

$so \Rightarrow ω_{1} = F_{1} \cdot d = 2 a - 2 b = - 8 \Rightarrow ω_{2} = F_{2} \cdot d = a + 5 b = 2 \dots\dots \Rightarrow a = - 3, b = 1$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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