Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

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Passage / Comprehension

A particle of mass 10 kg is projected from a horizontal surface with a velocity of 20 m/s at an angle of 60° with the horizontal. When it hits the horizontal surface, its velocity makes an angle of 30° with the horizontal. Apart from gravity, a horizontal force acts on the particle during the motion (g = 10 m/s $^{2}$ ).

The work done by the horizontal force during the complete motion is:-

Options:

Answer:

Solution:

Gravity does zero net work over the full flight (same level), so the horizontal force's work equals the KE change:

$W = \frac{1}{2} (10) [(203)^{2} - 2 0^{2}] = 5 \times 800 = 4000 J$

Ans. (D)

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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