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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2018

PhysicsEasysingle choice

In a single slit diffraction the distance between plane of slit and screen is $1 m$ . The size of the slit is $0.7 mm$ and second maximum is formed at the distance of $2 mm$ from the centre of the screen, then find out the wavelength of light.

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Answer:

Solution:

For second maxima path difference, $a tan θ = \frac{5 λ}{2}; a \cdot \frac{y}{D} = \frac{5 λ}{2} λ = \frac{2 a y}{5 D} = \frac{2 \times 0.7 \times 1 0 ^{- 3} \times 2 \times 1 0 ^{- 3}}{5 \times 1} = \frac{2.8}{5} \times 1 0^{- 6} m = \frac{28}{5} \times 1 0^{- 7} = 5600 \overset{˚}{A}$

Stream:AIIMSSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2018

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