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PhysicsWave OpticsYDSEHard2 minPYQ_2023
PhysicsHardnumerical

A beam of light consisting of two wavelengths 7000 Ao and 5500 Ao is used to obtain interference pattern in Young's double slit experiment. The distance between the slits is 2.5 mm and the distance between the plane of slits and the screen is 150 cm. The least distance from the central fringe, where the bright fringes due to both the wavelengths coincide, is n×105 m. The value of n is _____.

Answer:
462.00
Solution:

The given data is

λ1=7000 Ao

λ2=5500 Ao

d=2.5×10-3 m

D=1.5 m

The path difference is given by 

nλ1=mλ2

7n=5.5 m

14n=11 mn=11 and m=14

The formula for the distance of a bright fringe is

y=nλ1Dd

y=11×7×10-7×1.52.5×10-3

=46.2×10-4=462×10-5

It is given that 

n×10-5=462×10-5n=462

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE
2mℹ️ Source: PYQ_2023

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