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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEMedium2 minPYQ_2014

PhysicsMediumsingle choice

In the Young’s double slit experiment the intensity of light at a point on the screen where the path difference is $λ$ is $K,$ ( $λ$ being the wave length of light used). The intensity at a point where the path difference is $\frac{λ}{4},$ will be:NEET 2014

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Answer:

Solution:

$I_{m a x} = 4 I_{0} = K$
at the other point, path difference $= \frac{λ}{4}$
So, phase difference $ϕ = \frac{2 π}{λ} \times \frac{λ}{4} = \frac{π}{2}$
$I^{'} = I_{0} + I_{0} + 2 \sqrt{I_{0}} \sqrt{I_{0}} \cos \frac{π}{2}$
$I^{'} = 2 I_{0} = \frac{K}{2}$

Stream:NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2014

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