Physics - Wave Optics Question with Solution | TestHub

Given here, $\frac{I_1}{I_2}=\frac{1}{4}$ or $I_2=4I_1$

Maximum intensity is $I_{\max }={\left(\sqrt{I_1}+\sqrt{I_2}\right)}^2=I_1+4I_1+2\sqrt{I_{1}4I_1}=9I_1$

Minimum intensity is $I_{\min }={\left(\sqrt{I_1}-\sqrt{I_2}\right)}^2=I_1+4I_1-2\sqrt{I_{1}4I_1}=I_1$

The ratio of $\frac{I_{\max }+I_{\min }}{I_{\max }-I_{\min }}$ is 

 $\frac{9I_1+I_1}{9I_1-I_1}=\frac{10}{8}=\frac{5}{4}=\frac{2\alpha +1}{\beta +3}$

$\alpha =2 \beta =1$

$\therefore \frac{\alpha }{\beta }=\frac{2}{1}=2$