Two sources A and B of equal frequency give waves of amplitude a at P . Source A is ahead in phase by π /2 , and A P is longer than BP by 25 cm. For λ = 1 m the resultant amplitude at P is:

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Path difference 0.25 m gives a lag of π /2 for A . Net phase difference = π /2 − π /2 = 0 , so the waves add: 2 a .

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