A pulse is y = 1 + x 2 5 at t = 0 and y = 1 + ( x − 4 ) 2 5 at t = 2 s. Its speed in m/s is:

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A pulse is $y = \frac{5}{1 + x ^{2}}$ at $t = 0$ and $y = \frac{5}{1 + ( x - 4 ) ^{2}}$ at $t = 2$ s. Its speed in m/s is:

Answer:

Solution:

The pulse shifts 4 m in 2 s, so $v = 2$ m/s.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

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