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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringWavesMedium2 minQB

PhysicsMediumnumerical

A wire 50 cm long vibrates 100 times per second. If the length is shortened to 30 cm and the stretching force is quadrupled, what will be the frequency? (answer in $Hz$ ).

Answer:

333.30

Solution:

$f \propto \frac{1}{L} T$ . $f^{'} = 100 \times \frac{50}{30} \times 2 = 333.3$ Hz.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

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