Both the strings, shown in figure are made of same material and diameter of CD is double that of AB. The pulleys are light. The speed of a transverse wave in the string AB is $v_{1}$ and in CD it is $v_{2}$ , then $\frac{v _{1}}{v _{2}}$ is :

Question

diagram

TestHub · Accepted Answer

v = T / μ ​ . Light pulleys: T C D ​ = 2 T A B ​ ; diameter double gives μ C D ​ = 4 μ A B ​ . v 2 ​ v 1 ​ ​ = T C D ​ T A B ​ ​ ​ μ A B ​ μ C D ​ ​ ​ = 2 1 ​ ​ × 2 = 2 ​ - option (C).

Physics - Wave on String Question with Solution | TestHub

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JEE Main 2027 (Class 12)