Physics - Wave on String Question with Solution | TestHub

Comparing the given equation $y=10\cos (\pi x/15)\sin (48\pi t)$ with the standard equation of a stationary wave $y=A\cos (kx)\sin (\omega t)$, we get:

$k=\frac{\pi }{15}$

Since $k=\frac{2\pi }{\lambda }$, we have:

$\frac{2\pi }{\lambda }=\frac{\pi }{15}$

$\lambda =30\text{ cm}$

The distance between a node and the successive antinode is $\frac{\lambda }{4}$.

Distance $=\frac{30}{4}=7.5\text{ cm}$

Answer: $7.5\text{ cm}$