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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringEquation/graphEasy2 minPYQ_2020

PhysicsEasysingle choice

The velocity of sound waves in air is $330 m s^{- 1}$ . For a particular sound in air, a path difference of $40 c m$ is equivalent to a phase difference of $1.6 π$ . The frequency of this wave is

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Answer:

Solution:

Phase difference $= \frac{2 π}{λ} \times$ path difference

$\Rightarrow 1.6 π = \frac{2 π}{λ} \times 40$

$\Rightarrow λ = 50 cm = 0.5 m$

$\Rightarrow v = n λ$

$\Rightarrow 330 = 0.5 \times n$

$\Rightarrow n = 660 H z$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave on StringSubtopic:Equation/graph

⏱ 2mℹ️ Source: PYQ_2020

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