A 20 cm long rubber string obeys Hook\'s law. Initially when it is stretched to make its total length of 24 cm, the lowest frequency of resonance is n 0 . It is further stretched to make its to

Question

A 20 cm long rubber string obeys Hook\'s law. Initially when it is stretched to make its total length of 24 cm, the lowest frequency of resonance is n 0 ​ . It is further stretched to make its total length of 26 cm. The lowest frequency of resonance will now be:

TestHub · Accepted Answer

Tension T = k ( L − 20 ) and μ = m / L . n = 2 L 1 ​ T / μ ​ = 2 1 ​ m L k ( L − 20 ) ​ ​ ∝ L L − 20 ​ ​ . At 24 cm this is 4/24 ​ , at 26 cm 6/26 ​ . Since 6/26 > 4/24 , the frequency increases.

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