Start Free Mock LoginAlready registered? Login here

Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minQB

PhysicsEasysingle choice

A block of mass $m$ is attached to a cart of mass $4 m$ through spring of spring constant $k$ as shown in the figure. Friction is absent everywhere. The time period of oscillations of the system, when spring is compressed and then released, is

Options:

Answer:

Solution:

It is equivalent to a system as shown below,

$T = 2 π \sqrt{\frac{m_{reduced}}{k}}$

$∴ T = 2 π \sqrt{\frac{(\frac{m \times 4 m}{5 m})}{k}}$

$= 2 π \sqrt{\frac{4 m}{5 k}} = 4 π \sqrt{\frac{m}{5 k}}$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...