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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2021

PhysicsEasysingle choice

A particle is suspended from a vertical spring which is executing S.H.M. of frequency $5 Hz$ . The spring is unstretched at the highest point of oscillation. Maximum speed of the particle is $(g = 10 m / s^{2})$

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Answer:

Solution:

Amplitude of SHM, $A = \frac{mg}{k} = \frac{g}{ω ^{2}}$ $ω = 2 π f = 2 π \times 5 = 10 π ∴ A = \frac{10}{100 π ^{2}} = \frac{1}{10 π ^{2}} V_{m a x} = A ω = \frac{1}{10 π ^{2}} \times 10 π = \frac{1}{π} m / s$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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