A particle is executing simple harmonic motion with time period 2 s and amplitude 1 cm . If D and d are the total distance and displacement covered by the particle in 12.5 s , then d D is

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A particle is executing simple harmonic motion with time period 2 s and amplitude 1 cm . If D and d are the total distance and displacement covered by the particle in 12.5 s , then d D ​ is

TestHub · Accepted Answer

A = 1 cm ​ n = 2 12.5 ​ = 6.25 cycles ∴ D = 4 × 6 + 1 = 25 d = 1 d D ​ = 25 ​

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