Start Free Mock LoginAlready registered? Login here

Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle executing a simple harmonic motion has a period of $6 s$ . The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is

Options:

Answer:

Solution:

$y = A \sin (\frac{2 π}{T}) t$

$\frac{A}{2} = A \sin (\frac{2 π}{T}) t = \frac{2 π}{T} t = π / 6$

Time period $t = \frac{T}{12} = \frac{6}{12} = \frac{1}{2}$ s

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...