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PhysicsSHMMiscellaneousEasy2 minPYQ_2022

PhysicsEasysingle choice

The path length of oscillation of simple pendulum of length $1 m$ is $16 cm$ . its maximum velocity is (Take $g = π^{2} m / s^{2}$ )

Answer:

Solution:

Amplitude of SHM, $a = 8 cm$ Maximum velocity is given by, $v = aω = a \frac{g}{l} = 8 \times \frac{π ^{2}}{1} = 8 π cm / s$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2022

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