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PhysicsSHMCalculation of time periodHard2 minPYQ_2013
PhysicsHardsingle choice

An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass M. The piston and the cylinder have equal cross-sectional area A. When the piston is in equilibrium, the volume of the gas is V0 and its pressure is M0. The piston is slightly displaced from the equilibrium position and released. Assuming that the system is completely isolated from its surrounding, the piston executes a simple harmonic motion with frequency
[Assume the system is in space.]

Question diagram: An ideal gas enclosed in a vertical cylindrical container su

Options:

Answer:
A
Solution:

For an adiabatic process,

Pvγ=constant

Differentiating with respect tov,

dPdvvγ+Pγvγ-1=0

dP=-γPvdv=-γPvAdx



Thus, the acceleration,a=dFM=γPA2MVdx

Comparing with ,a=-ω2dx, we get,

ω=γP0A2MV0=2πf


f=12πγP0A2MV0

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period
2mℹ️ Source: PYQ_2013

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