The maximum potential energy of a block executing simple harmonic motion is 25 J . A is amplitude of oscillation. At A 2 , the kinetic energy of the block is

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The maximum potential energy of a block executing simple harmonic motion is given by $U_{\max} = \frac{1}{2} m ω^{2} A^{2} = 25 J$

As, kinetic energy of particle executing SHM is $K E = \frac{1}{2} m ω^{2} (A^{2} - x^{2})$ .

So, kinetic energy of block $K E at \frac{A}{2} = \frac{1}{2} m v_{1}^{2} = \frac{1}{2} m ω^{2} (A^{2} - \frac{A^{2}}{4})$

$\Rightarrow K E = \frac{1}{2} m ω^{2} \frac{3 A^{2}}{4} = \frac{3}{4} (\frac{1}{2} m ω^{2} A^{2})$

$\Rightarrow K E = \frac{3}{4} \times 25 = 18.75 J$

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