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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A simple pendulum $4 m$ long swings with an amplitude of $0.2 m$ . The acceleration at the ends of its path is $(g = 10 m s^{- 2})$

Options:

Answer:

Solution:

$T = m g \cos θ$

$∴ F_{n e t} = m g \sin θ$

and $a c c e l e r a t i o n = g \sin θ = g \tan θ (\sin θ ≅ \tan θ, for small value of θ)$

$= (10) \frac{(0.2)}{4} = 0.5 m s^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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