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Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

The equation of simple harmonic motion of a particle is $a + 4 π^{2} x = 0$ where $a$ is the instantaneous linear acceleration at displacement $x$ . The frequency of motion is

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Solution:

Comparing $a + 4 π^{2} x = 0$ with standard equation of simple harmonic motion $a + ω^{2} x = 0$

$ω^{2} = 4 π^{2}, ω = 2 π$

$2 π n = 2 π, n = 1 Hz$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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