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PhysicsSHMCalculation of time periodMedium2 minQB
PhysicsMediummatching list

The 5 kg block in the figure is pulled with a constant velocity of . Initially springs are in natural length and 3kg block is at rest. (Take : and K = 10 N/m)

figure

List-I

List-II

(P) Time after which velocity of 3 kg block becomes (in sec)

(1) 40

(Q) Time after which 3 kg block comes to rest again (in sec)

(2) 2/3

(R) Displacement of 5 kg block when relative velocity between the blocks is zero (in m)

(3) 60

(S) External force required on 5 kg block when 3 kg block comes to rest again (in N)

(4) 2

 

(5) 10

Options:

Answer:
A
Solution:

In the frame moving with 2V/3, the 3 kg block executes SHM with

 

(P) Block regains velocity V⃗ after

 

(Q) Block comes to rest again after

 

(R) Relative velocity zero at t = T/3: displacement of 5 kg block

 

(S) When 3 kg is at rest again, spring 2K is stretched by 2 m ⇒ external force

 

Hence (A).

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period
⏱ 2mℹ️ Source: QB

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