A point object performs SHM about mean position $x = 25 cm$ , in front of a concave mirror of focal length 10 cm. Position of the particle about the mean position is given $x = 5 sin 9 t$ (in cm).
What is the speed of image (in cm/s) when object is at its mean position.

Question

A point object performs SHM about mean position $x = 25 cm$ , in front of a concave mirror of focal length 10 cm. Position of the particle about the mean position is given $x = 5 sin 9 t$ (in cm).

What is the speed of image (in cm/s) when object is at its mean position.

TestHub · Accepted Answer

Mean position: object distance u = 25 cm , f = 10 cm , so v = 3 50 ​ cm . Longitudinal image speed: v i ​ = u 2 v 2 ​ v o ​ ; object speed at mean v o ​ = A ω = 5 × 9 = 45 cm / s . v i ​ = ( 25 50/3 ​ ) 2 × 45 = 9 4 ​ × 45 = 20 cm / s Answer: 20.00

Physics - SHM Question with Solution | TestHub

Doubts & Discussion