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PhysicsSHMCalculation of time periodMedium2 minPYQ_2015

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A particle is executing a simple harmonic motion. Its maximum acceleration is $α$ and maximum velocity is $β$ . Then, its time period of vibration will be:NEET 2015 (Phase 2)

Options:

Answer:

Solution:

$ω^{2} A = α$

$ω A = β$

$\Rightarrow ω = \frac{α}{β}$

$\Rightarrow T = \frac{2 π}{ω} = \frac{2 π β}{α}$

Stream:NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2015

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