Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minPYQ_2021

PhysicsEasysingle choice

A spring is stretched by $5 cm$ by a force $10 N$ . The time period of the oscillations when a mass of $2 kg$ is suspended by it is :NEET 2021

Answer:

Solution:

Spring force, $F = k x$

Spring constant, $k = \frac{F}{x} = \frac{10}{0.05} = 200 \frac{N}{m}$

Time period, $T = 2 π \sqrt{\frac{m}{k}}$

$T = 2 π \sqrt{\frac{2}{200}} = 0.2 π = 0.628 s$

Stream:NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2021

Loading discussions...