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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMHard2 min

PhysicsHardnumerical

A 0.5 kg particle in SHM with $ω = 10$ rad/s and amplitude 0.2 m gets a blow of impulse 2 N s along its motion at $x = 0.1$ m. Find the new amplitude, in m.

Answer:

0.58

Solution:

$v = 10 0.04 - 0.01 = 1.732$ m/s, $v_{n e w} = 1.732 + 4 = 5.732$ . $A^{2} = 0.01 + 0.5732^{2}$ , $A = 0.582$ m.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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