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PhysicsRotationCalculation of M.I.Hard2 minPYQ_2023
PhysicsHardnumerical

A solid sphere and a solid cylinder of same mass and radius are rolling on a horizontal surface without slipping. The ratio of their radius of gyrations respectivelyksph:kcylis2:x. The value ofxis _______.

Answer:
5.00
Solution:

Considering rotational axis as the diametrical axis for sphere and axis of cylinder. Then

K12=25R2 and K22=12R2

 K1K2=2/51/2=45

K1K2=25

Comparing it with the given value in the question,

25=2x

 x=5

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.
2mℹ️ Source: PYQ_2023

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