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Physics - Rotation Question with Solution | TestHub

PhysicsRotation286Hard2 minQB

PhysicsHardsingle choice

A thin rod of mass m and length 1 is hinged at one end point which is at a distance $h (h < ℓ)$ above the horizontal surface. The rod is released from rest from the horizontal position. If e is the coefficient of restitution, the angular velocity of rod just after collision will be :- $(h = 1 m, ℓ = 2 m, e = 1)$

Options:

Answer:

Solution:

$m g \frac{ℓ}{2} sin 3 0^{\circ} = \frac{1}{2} \times \frac{m ℓ ^{2}}{3} ω^{2}$ , so $ω = \frac{3 g}{2 ℓ} = \frac{3 g}{2}$

With e = 1 the rod rebounds with the same angular speed: $ω^{'} = ω$

Answer (D)

Stream:JEESubject:PhysicsTopic:RotationSubtopic:286

⏱ 2mℹ️ Source: QB

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