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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2020

PhysicsEasysingle choice

Four solid spheres each of mass $M$ and radius $R$ are placed at four corners of a light square frame of side length $4 R$ such that centres of spheres coincide with corners of the square. What will be the moment of inertia of the system about an axis normal to the plane of the frame and passing through its centre?

Options:

Answer:

Solution:

$I = 4 I_{1}$

Where $I_{1}$ is MI of each sphere

$I_{1} = I_{c} + M d^{2}$

And $I_{c} = \frac{2}{5} M R^{2}$ ; $d = \frac{L}{\sqrt{2}}$ ; $L = 4 R$

Subject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2020

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