Physics - NLM Question with Solution | TestHub

Let the acceleration of the system be $a$ and the tension in the string be $T$. For block $m_1$: $T=m_{1}a$. For block $m_2$: $m_{2}g-T=m_{2}a$. Substitute $T$ from the first equation into the second: $m_{2}g-m_{1}a=m_{2}a$. This gives $a=\frac{m_{2}g}{m_1+m_2}$. Now, substitute $a$ back into the equation for $T$: $T=m_{1}a=m_1\left(\frac{m_{2}g}{m_1+m_2}\right)=\frac{m_1{m}_{2}g}{m_1+m_2}$.