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Physics - NLM Question with Solution | TestHub

PhysicsNLMMedium2 minQB

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A cubical block of mass $2 kg$ is sliding down on a smooth inclined right angled trough as shown in the figure. The two adjacent surfaces of cube are always in contact with the trough. Then the net reaction force on the block is

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Answer:

Solution:

$N_{1} cos 45 + N_{2} cos 45 = mg$

but by symmetry $N_{1} = N_{2}$

$\Rightarrow N = \frac{mg}{2 cos 45} = \frac{2 \times 10}{2 \times \frac{1}{2}}$

$= 10 newton$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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