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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMMedium2 minQB

PhysicsMediumsingle choice

Force $F$ is applied on the upper pulley, $F = 30 t$ N where $t$ is time in seconds. Find the time when $m_{1}$ loses contact with the floor: $m_{1} = 4$ kg, $m_{2} = 1$ kg, the string geometry is as shown in the figure. (Take $g = 10$ m/s²)

Options:

Answer:

Solution:

$m_{1}$ loses contact when the normal reaction on it becomes zero.
With the printed pulley-string geometry the book obtains
$F = 3 T$
with
$T = 10 t$
N, and the lift-off condition gives
$30 t = 60$
i.e.
$t = 2 s .$
Option C.

Subject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

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