Start Free Mock LoginAlready registered? Login here

Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionEasy2 minPYQ_2022

PhysicsEasysingle choice

A block of mass $40 kg$ slides over a surface, when a mass of $4 kg$ is suspended through an inextensible massless string passing over frictionless pulley as shown below.
The coefficient of kinetic friction between the surface and block is $0.02$ . The acceleration of block is: (Given $g = 10 {m s}^{- 2}$ .)

Options:

Answer:

Solution:

For hanging block,

$40 - T = 4 a \dots (1)$

Now, maximum value of friction force will be,

$f_{m a x} = μ N = 0.02 \times 40 \times 10 = 8 N$

For block on table, $T - 8 = 40 a \dots (2)$

From equation(1) and equation (2), we get $32 = 44 a \Rightarrow a = \frac{32}{44} = \frac{8}{11} m s^{- 2}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...