A block of mass 40 kg slides over a surface, when a mass of 4 kg is suspended through an inextensible massless string passing over frictionless pulley as shown below. The coefficient of kinetic fricti

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A block of mass 40 kg slides over a surface, when a mass of 4 kg is suspended through an inextensible massless string passing over frictionless pulley as shown below. The coefficient of kinetic friction between the surface and block is 0 . 02 . The acceleration of block is: (Given g = 10 m s - 2 .)

TestHub · Accepted Answer

For hanging block, 40 - T = 4 a ⋯ 1 Now, maximum value of friction force will be, f m a x = μ N = 0 . 02 × 40 × 10 = 8 N For block on table, T - 8 = 40 a ⋯ 2 From equation(1) and equation (2), we get 32 = 44 a ⇒ a = 32 44 = 8 11 m s - 2

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