In the given nuclear reaction, the element X is Na 11 22 → X + e + + v NEET 2022 (Phase 1)

As positron is emitting, it is positive beta decay with equation, X z A ⟶ Y z - 1 A + e + + ν Hence, ⇒ Na 11 22 ⟶ Ne 10 22 + e + + ν

Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsNuclear physicsEasy2 minPYQ_2022

PhysicsEasysingle choice

In the given nuclear reaction, the element $X$ is ${}_{11}^{22}{Na} \to X + e^{+} + v$ NEET 2022 (Phase 1)

Answer:

Solution:

As positron is emitting, it is positive beta decay with equation,

${}_{z}^{A}X ⟶ {}_{z - 1}^{A}Y + e^{+} + ν$

Hence, $\Rightarrow {}_{11}^{22}{Na} ⟶ {}_{10}^{22}{Ne} + e^{+} + ν$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2022

Loading discussions...