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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

A proton and anα-particle, accelerated through the same potential difference, enter in a uniform magnetic field normally. If the radius of the proton orbit is10 cm, then the radius ofα-particle is

Options:

Answer:
B
Solution:

R=mvqB

RαRp=mαvαqαmpvpqp=2vαvp

Beacuse

qα=2qp

mα=4mp

as they are acclerated by same potential

Equation of α=qαV=2qp V 

12mα×Vα2=212mPVp2

VαVP=12

HenceRαRP=2×12=2

Rα=2RP =102 cm

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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