Physics - Modern Physics Question with Solution | TestHub

${}_1^2\mathrm{H}+{}_1^2\mathrm{H}\stackrel{}{\to }{}_2^4\mathrm{He}$

The binding energy of two deuterons =$2\times [1.1\times 2]=4.4\mathrm{MeV}$

The binding energy of one helium nucleus =$4\times 7=28\mathrm{MeV}$

$\therefore$the total energy released when two deuterons fuse to form a helium nucleus$=28-4.4=23.6\mathrm{MeV}$