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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

Light of energy $2.0 eV$ falls on a metal of work function $1.4 eV$ . The stopping potential is

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Answer:

Solution:

From Planck's quantum theory, the maximum kinetic energy ( $E_{k}$ ) of photoelectron emitted from the metal is

$E_{k} = h v - W$

Where W is work function of metal andhv is the energy of the photon absorbed by the metal.

Given, $h v = 2 e V, W = 1.4 e V$

$∴ E_{k} = 2 - 1.4 = 0.6$ eV

Hence, stopping potential is , $V_{s} = \frac{E}{e} = \frac{0.6 e V}{e} = 0.6 V .$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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