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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

According to Bohr's model, the minimum energy (in $eV$ ) required to remove an electron from the ground state of a doubly ionized $Li$ atom $(Z = 3)$ is

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Answer:

Solution:

The doubly ionized $Li$ atom is $H$ -like atom

$E_{n} = - \frac{13.6 Z^{2}}{n^{2}} eV$

The ground state energy of the doubly ionised $Li$ atom

$(Z = 3, n = 1)$ will be

$E_{1} = \frac{- 13.6 \times 9}{1} = - 122.4 eV$

Hence, the ionisation energy for an electron in the ground state of doubly ionised $Li$ atom $= 122.4 eV$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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