Physics - Modern Physics Question with Solution | TestHub

$\lambda =6840\mathring{A}$ $\therefore \mathrm{v}=\frac{c}{\lambda }\Rightarrow h\mathrm{v}=\frac{hc}{\lambda };hc=12400\mathrm{eV}\mathring{A}$ Energy of the photon $=\frac{12400\mathrm{eV}\mathring{A}}{6840\mathring{A}}=1.81\mathring{A}$