Physics - Modern Physics Question with Solution | TestHub

Given,$\Delta \text{m}$for${}_5{\text{B}}^{11}=\text{0.0821 u}$

Number of nucleons$=\text{11}$

​Binding energy$=\left(931\times \Delta \text{m}\right)\text{MeV}$

$=931\times \text{0.081}$

$=\text{75.411 MeV}$

Average binding energy

$=\frac{\text{Binding energy}}{\text{Number of nucleons}}$

$=\frac{\text{75.411}}{\text{11}}$

$=\text{6.85 MeV}$