Start Free Mock LoginAlready registered? Login here

Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

An $α$ -particle of energy $5 M e V$ is scattered through $180 °$ by a stationary uranium nucleus. The distance of closest approach is of the order

Options:

Answer:

Solution:

According to work energy theorem

$K E = P E$

$K E = \frac{1}{4 π ε_{0}} \frac{q_{1} q_{2}}{r}$

$r = \frac{1}{4 π ε_{0}} \frac{92 e \cdot 2 e}{E}$

$r = \frac{9 \times 1 0^{9} \times 92 \times 2 {(1.6 \times 1 0^{- 19})}^{2}}{5 \times 1 0^{6} \times (1.6 \times 1 0^{- 19})}$

$r = 5.3 \times 1 0^{- 14} m \approx 1 0^{- 12} c m .$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...