In an experiment on photoelectric effect, a student plots stopping potential $V_{0}$ against reciprocal of the wavelength $λ$ of the incident light for two different metals $A$ and $B$ . These are shown in the figure.
Looking at the graphs, you can most appropriately say that:

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TestHub · Accepted Answer

​ λ hc ​ − ϕ = eV 0 ​ v 0 ​ = e λ hc ​ − e ϕ ​ ​ As the value of λ 1 ​ (increasing and decreasing) is not specified hence we cannot say that which metal has comparatively greater or lesser work function ( ϕ ) .

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