A sample has half life of 1 0 33 year. If initial number of nuclei of the sample is 26 × 1 0 34 . Then find out the number of nuclei decayed in 1 year.

− d t d N = λ N − d N = T 1/2 ln 2 × N × d t = 1 0 33 0.7 × 26 × 1 0 34 × 1 = 182.

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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsRadioactivityMedium2 minPYQ_2019

PhysicsMediumsingle choice

A sample has half life of $1 0^{33}$ year. If initial number of nuclei of the sample is $26 \times 1 0^{34}$ . Then find out the number of nuclei decayed in 1 year.

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Solution:

$- \frac{d N}{d t} = λ N - d N = \frac{ln 2}{T _{1/2}} \times N \times d t = \frac{0.7}{1 0 ^{33}} \times 26 \times 1 0^{34} \times 1 = 182.$

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2019

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