The energy levels in an atom A , B and C are in increasing order E A < E B < E C . The x-rays emitted in transitions C → B , B → A and C → A , have wavelengths λ 1 , λ 2 and λ 3 then which of the following relation is true?

As E A < E B < E C Therefore C is higher energy level & A is at lowest E C → A = E C → B + E B → A h c λ 3 = h c λ 1 + h c λ 2 therefore λ 3 = λ 1 λ 2 λ 1 + λ 2

Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The energy levels in an atom $A, B$ and $C$ are in increasing order $E_{A} < E_{B} < E_{C}$ . The x-rays emitted in transitions $C \to B, B \to A$ and $C \to A$ , have wavelengths $λ_{1}, λ_{2}$ and $λ_{3}$ then which of the following relation is true?

Options:

Answer:

Solution:

As $E_{A} < E_{B} < E_{C}$

Therefore C is higher energy level & A is at lowest

$E_{C \to A} = E_{C \to B} + E_{B \to A}$

$\frac{h c}{λ_{3}} = \frac{h c}{λ_{1}} + \frac{h c}{λ_{2}}$

therefore

$λ_{3} = \frac{λ_{1} λ_{2}}{λ_{1} + λ_{2}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...