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PhysicsModern PhysicsAtomic structureMedium2 minQB

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The energy of an electron in an excited hydrogen atom is -3.4 eV. The angular momentum of the electron in this state in accordance with Bohr's theory is:

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Answer:

Solution:

$E = - 3.4 eV \Rightarrow n = 2. L = \frac{nh}{2 π} = \frac{h}{π} = 2.11 \times 1 0^{- 34} \approx 2.10 \times 1 0^{- 34} J s$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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