The difference between threshold wavelengths for two metal surfaces $A$ and $B$ having work function $ϕ_{A} = 9 eV$ and $ϕ_{B} = 4.5 eV$ in $nm$ is:
{Given, $h c = 1242 eV nm$ }

Question

The difference between threshold wavelengths for two metal surfaces A and B having work function ϕ A = 9 eV and ϕ B = 4 . 5 eV in nm is: {Given, h c = 1242 eV nm }

TestHub · Accepted Answer

The work function is given by h c λ = ϕ ⇒ λ = h c ϕ By the given data, λ A = 1242 9 nm , λ B = 1242 4 . 5 nm , The difference between the wavelengths, λ B - λ A = 1242 4 . 5 - 1242 9 nm = 1242 9 nm = 138 nm

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