Physics - Modern Physics Question with Solution | TestHub

Given the nuclear reaction is

${}_6\mathrm{C}^{13}+\mathrm{Energy}\to {}_6\mathrm{C}^{12}+{}_0\mathrm{n}^1$

The mass defect for the above reaction can be calculated as follows:

$\begin{array}{rcl}\Delta \mathrm{m}& =& \left[(12.000000+1.008665)-13.003354\right] \mathrm{u}\\ & =& -0.00531 \mathrm{u}\end{array}$

Hence, the energy required is given by

$\begin{array}{rcl}E& =& 0.00531\times 931.5 \mathrm{MeV}\\ & =& 4.95 \mathrm{MeV}\end{array}$