Physics - Modern Physics Question with Solution | TestHub

Energy of photon emitted

$\mathrm{E}=\frac{13.6}{1^2}-\frac{13.6}{3^2}$

$\mathrm{E}=12.09\mathrm{ }\mathrm{e}\mathrm{V}$

Momentum of photon,

$\frac{\mathrm{E}}{\mathrm{c}}=\frac{12.09\times 1.6\times 10^{-19}}{3\times 10^8}\mathrm{ }\mathrm{N}\mathrm{s}=6.45\times 10^{-27}\mathrm{ }\mathrm{N}\mathrm{ }\mathrm{s}$

Same will be the magnitude of recoil momentum of$\mathrm{H}$atom